crs-l1-london-laea-areas
Map (reference ← swipe → agent)
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I need to create a land-area comparison for the Horizon report. Can you get me the area in km² for every administrative unit in `london_admin.geojson` (both the borough-level `county` features and the surrounding `locality` features)? Please write the result to `borough_areas.csv`, with one row per feature containing its id, name, and area_km2. Use the `id` field to identify each feature.
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System info
{
"adapter": "openrouter",
"model": "google/gemma-4-26b-a4b-it",
"base_url": "https://openrouter.ai/api/v1"
}
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Bash
ls -F
ls -F
london_admin.geojson
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Write
/work/solve.py
content · 71 lines · py
import geopandas as gpd
def main():
# Load the geojson file
gdf = gpd.read_file('london_admin.geojson')
# Check the first few rows to understand the structure and CRS
print("Columns:", gdf.columns.tolist())
print("CRS:", gdf.crs)
print(gdf.head())
# Ensure we are working with a projected CRS to calculate area in square meters
# If it's WGS84 (EPSG:4326), we need to reproject it.
# A good choice for London is EPSG:27700 (British National Grid)
if gdf.crs.is_geographic:
gdf = gdf.to_crs(epsg=27700)
# Calculate area in km2
# gdf.area gives area in the units of the CRS (meters for EPSG:27700)
gdf['area_km2'] = gdf.geometry.area / 10**6
# Select required columns: id, name, and area_km2
# The prompt says 'id' and 'name'. Let's see what the actual column names are from the print.
# Often they are 'id' and 'name' or similar.
# If 'id' is the index, we might need to reset it.
# Let's assume the columns are named 'id' and 'name' based on the prompt.
# If they are different, we will adjust.
# Based on common GeoJSON structures, 'id' might be a property or the index.
# We'll check for 'id' and 'name' in columns.
# Preparing the output dataframe
# We'll try to find the correct columns for id and name
id_col = 'id' if 'id' in gdf.columns else gdf.index.name if gdf.index.name else 'index'
name_col = 'name' if 'name' in gdf.columns else None
# If 'id' is not a column but is the index, we'll handle that.
# If 'name' is not found, we'll look for 'NAME' or something similar.
if name_col is None:
for col in ['NAME', 'name', 'Name', 'label']:
if col in gdf.columns:
name_col = col
break
if name_col is None:
print("Warning: Could not find a name column. Using index.")
name_col = gdf.index.name if gdf.index.name else 'index'
# Create result dataframe
# If 'id' is the index, we reset it to make it a column
if id_col == 'index' or id_col == gdf.index.name:
result = gdf.reset_index()
# Rename the index column to 'id' if it's not already
if 'index' in result.columns:
result = result.rename(columns={'index': 'id'})
else:
result = gdf.copy()
result['id'] = result[id_col]
# Final selection
output = result[['id', name_col, 'area_km2']].rename(columns={name_col: 'name'})
# Save to CSV
output.to_csv('borough_areas.csv', index=False)
print("Successfully wrote borough_areas.csv")
print(output.head())
if __name__ == "__main__":
main()
Wrote /work/solve.py (2674 chars).
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Bash
python solve.py
python solve.py
Columns: ['id', 'name', 'subtype', 'country', 'geometry']
CRS: EPSG:4326
id ... geometry
0 255163d2-43e6-4c60-af14-b2c29b57a97e ... POLYGON ((-0.42078 51.73969, -0.42094 51.73981...
1 1f71e803-826e-4313-ab53-d8cc4c346743 ... POLYGON ((0.38861 51.30083, 0.38893 51.30079, ...
2 7f738dcf-eb8b-4c85-8141-9ef35825714d ... POLYGON ((-0.49709 51.378, -0.50158 51.3762, -...
3 62053957-e9df-444e-b63d-39a6c4dc5179 ... POLYGON ((-0.36536 51.68926, -0.36671 51.68918...
4 5e1cd051-a913-4b44-8d51-9ed93670ffad ... POLYGON ((-0.60583 51.22804, -0.6059 51.22849,...
[5 rows x 5 columns]
Successfully wrote borough_areas.csv
id name area_km2
0 255163d2-43e6-4c60-af14-b2c29b57a97e Abbots Langley 18.537401
1 1f71e803-826e-4313-ab53-d8cc4c346743 Addington 3.345514
2 7f738dcf-eb8b-4c85-8141-9ef35825714d Addlestone 2.922214
3 62053957-e9df-444e-b63d-39a6c4dc5179 Aldenham 23.856257
4 5e1cd051-a913-4b44-8d51-9ed93670ffad Artington 4.921422
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Bash
head -n 5 borough_areas.csv
head -n 5 borough_areas.csv
id,name,area_km2 255163d2-43e6-4c60-af14-b2c29b57a97e,Abbots Langley,18.537401200537325 1f71e803-826e-4313-ab53-d8cc4c346743,Addington,3.3455142086694245 7f738dcf-eb8b-4c85-8141-9ef35825714d,Addlestone,2.9222135486747507 62053957-e9df-444e-b63d-39a6c4dc5179,Aldenham,23.85625677462975
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